F(x-3)=x^2+5x+8

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Solution for F(x-3)=x^2+5x+8 equation: 



(F-3)=F^2+5F+8

We move all terms to the left:

(F-3)-(F^2+5F+8)=0

We get rid of parentheses

-F^2+F-5F-3-8=0

We add all the numbers together, and all the variables

-1F^2-4F-11=0

a = -1; b = -4; c = -11;
Δ = b2-4ac
Δ = -42-4·(-1)·(-11)
Δ = -28
Delta is less than zero, so there is no solution for the equation

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